(3/5)q^2-4q+160=0

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Solution for (3/5)q^2-4q+160=0 equation: 


q in (-oo:+oo)

(3/5)*q^2-(4*q)+160 = 0

(3/5)*q^2-4*q+160 = 0

3/5*q^2-4*q+160 = 0

DELTA = (-4)^2-(3/5*4*160)

DELTA = -368

DELTA < 0

q belongs to the empty set

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